Strings and Numbers

Strings¶

import string as s

Command	Description
`s.ascii_letters`	abc...zABC....Z
`S.ascii_lowercase`	abc.....z
`S.ascii_uppercase`	ABCD....Z
`S.digits`	0123456789
`S.hexdigits`	0123456789abcdefABCDEF
`S.octdigits`	01234567
`S.punctutaion`	!"#$%&'()*+,-./:;<=>?@[\]^_`{}~
`S.whitespace`	Space, tab, return
`S.printable`	0123456789 abcdefghijklmnopqrstuvwxyz ABCDEFGHIJKLMNOPQRSTUVWXYZ !"#$%&'()*+,-./:;<=>?@[]^_`{}~

mystr = "Abhishek"

Command	Description
`mystr.capitalize()`	Abhishek
`mystr.count(substr, start, end)`	Count number of substr present in mystr[start: end]
`mystr.encode(encoding='utf-8')`	b'abhishek'
`mystr.find(substr, start, end)` `mystr.rfind()`	Returns index of substring if found rfind finds substring from right side of mystr
`mystr.index('shek')`	4; Just like find(), but it gives error if substring not found
`mystr.islower()`	True
`mystr.partition('s')`	('abhi', 's', 'hek')
`mystr.replace(old, new, count)`	Replces old substring with new upto count number of times
`mystr.startswith('abhi')`	True
`mystr.strip('abc')`	Strips a, b, c from both sides of the string
`mystr.zfill(width)`	Fill each side of mystr with 0 to obtain 'width' length
`mystr.join(mystr2)`	better than mystr + mystr2 because + make a third new string resulting in a quadratic runtime cost
`mystr.swapcase()`	return string after changing cases of each character
`mystr.title()`	'Hello dev'.title() ==> Hello Dev
`mystr.endswith(('abc', 'xyz', 'pqr'))`	False
`mystr.` `isalpha()` `isdecimal()` `isdigit()` `isidentifier()` `isnumeric()` `isspace()` `istitle()`	Self explainatory
`mystr.` `center(length, fillchar)` `ljust(length, fillchar)` `rjust(length, fillchar)` `lstrip('chars')`	Fill both sides of string by 'fillchar' upto given length lstrip: The chars argument is a string specifying the set of characters to be removed

Command	Description
`abs(num)`	absolute value
`round(num, upto)`	rounded up number upto decimals
`int(num)`	cast to integer